Optimal. Leaf size=267 \[ -\frac {b \cos ^6(c+d x)}{3 a^3 d}+\frac {\cos ^7(c+d x)}{7 a^2 d}+\frac {b^2 \left (a^2-b^2\right )^3}{a^9 d (a \cos (c+d x)+b)}+\frac {2 b \left (a^2-4 b^2\right ) \left (a^2-b^2\right )^2 \log (a \cos (c+d x)+b)}{a^9 d}-\frac {\left (a^2-7 b^2\right ) \left (a^2-b^2\right )^2 \cos (c+d x)}{a^8 d}-\frac {3 b \left (a^2-b^2\right )^2 \cos ^2(c+d x)}{a^7 d}+\frac {b \left (3 a^2-2 b^2\right ) \cos ^4(c+d x)}{2 a^5 d}-\frac {3 \left (a^2-b^2\right ) \cos ^5(c+d x)}{5 a^4 d}+\frac {\left (3 a^4-9 a^2 b^2+5 b^4\right ) \cos ^3(c+d x)}{3 a^6 d} \]
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Rubi [A] time = 0.37, antiderivative size = 267, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3872, 2837, 12, 948} \[ -\frac {3 \left (a^2-b^2\right ) \cos ^5(c+d x)}{5 a^4 d}+\frac {b \left (3 a^2-2 b^2\right ) \cos ^4(c+d x)}{2 a^5 d}+\frac {\left (-9 a^2 b^2+3 a^4+5 b^4\right ) \cos ^3(c+d x)}{3 a^6 d}-\frac {3 b \left (a^2-b^2\right )^2 \cos ^2(c+d x)}{a^7 d}-\frac {\left (a^2-7 b^2\right ) \left (a^2-b^2\right )^2 \cos (c+d x)}{a^8 d}+\frac {b^2 \left (a^2-b^2\right )^3}{a^9 d (a \cos (c+d x)+b)}+\frac {2 b \left (a^2-4 b^2\right ) \left (a^2-b^2\right )^2 \log (a \cos (c+d x)+b)}{a^9 d}-\frac {b \cos ^6(c+d x)}{3 a^3 d}+\frac {\cos ^7(c+d x)}{7 a^2 d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 948
Rule 2837
Rule 3872
Rubi steps
\begin {align*} \int \frac {\sin ^7(c+d x)}{(a+b \sec (c+d x))^2} \, dx &=\int \frac {\cos ^2(c+d x) \sin ^7(c+d x)}{(-b-a \cos (c+d x))^2} \, dx\\ &=\frac {\operatorname {Subst}\left (\int \frac {x^2 \left (a^2-x^2\right )^3}{a^2 (-b+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a^7 d}\\ &=\frac {\operatorname {Subst}\left (\int \frac {x^2 \left (a^2-x^2\right )^3}{(-b+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a^9 d}\\ &=\frac {\operatorname {Subst}\left (\int \left (\left (a^2-7 b^2\right ) \left (a^2-b^2\right )^2-\frac {b^2 \left (-a^2+b^2\right )^3}{(b-x)^2}+\frac {2 b \left (-a^2+b^2\right )^2 \left (-a^2+4 b^2\right )}{b-x}-6 b \left (-a^2+b^2\right )^2 x-\left (3 a^4-9 a^2 b^2+5 b^4\right ) x^2-2 b \left (-3 a^2+2 b^2\right ) x^3+3 \left (a^2-b^2\right ) x^4-2 b x^5-x^6\right ) \, dx,x,-a \cos (c+d x)\right )}{a^9 d}\\ &=-\frac {\left (a^2-7 b^2\right ) \left (a^2-b^2\right )^2 \cos (c+d x)}{a^8 d}-\frac {3 b \left (a^2-b^2\right )^2 \cos ^2(c+d x)}{a^7 d}+\frac {\left (3 a^4-9 a^2 b^2+5 b^4\right ) \cos ^3(c+d x)}{3 a^6 d}+\frac {b \left (3 a^2-2 b^2\right ) \cos ^4(c+d x)}{2 a^5 d}-\frac {3 \left (a^2-b^2\right ) \cos ^5(c+d x)}{5 a^4 d}-\frac {b \cos ^6(c+d x)}{3 a^3 d}+\frac {\cos ^7(c+d x)}{7 a^2 d}+\frac {b^2 \left (a^2-b^2\right )^3}{a^9 d (b+a \cos (c+d x))}+\frac {2 b \left (a^2-4 b^2\right ) \left (a^2-b^2\right )^2 \log (b+a \cos (c+d x))}{a^9 d}\\ \end {align*}
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Mathematica [A] time = 3.61, size = 417, normalized size = 1.56 \[ \frac {588 a^8 \cos (4 (c+d x))-132 a^8 \cos (6 (c+d x))+15 a^8 \cos (8 (c+d x))-3675 a^8-3780 a^7 b \cos (3 (c+d x))+476 a^7 b \cos (5 (c+d x))-40 a^7 b \cos (7 (c+d x))-1848 a^6 b^2 \cos (4 (c+d x))+112 a^6 b^2 \cos (6 (c+d x))+26880 a^6 b^2 \log (a \cos (c+d x)+b)+61320 a^6 b^2+8400 a^5 b^3 \cos (3 (c+d x))-336 a^5 b^3 \cos (5 (c+d x))+1120 a^4 b^4 \cos (4 (c+d x))-161280 a^4 b^4 \log (a \cos (c+d x)+b)-132720 a^4 b^4-4480 a^3 b^5 \cos (3 (c+d x))+241920 a^2 b^6 \log (a \cos (c+d x)+b)+87360 a^2 b^6+1680 a b \cos (c+d x) \left (-8 a^6+67 a^4 b^2-116 a^2 b^4+16 \left (a^2-4 b^2\right ) \left (a^2-b^2\right )^2 \log (a \cos (c+d x)+b)+56 b^6\right )-140 \left (21 a^8-228 a^6 b^2+400 a^4 b^4-192 a^2 b^6\right ) \cos (2 (c+d x))-107520 b^8 \log (a \cos (c+d x)+b)-13440 b^8}{13440 a^9 d (a \cos (c+d x)+b)} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.82, size = 344, normalized size = 1.29 \[ \frac {120 \, a^{8} \cos \left (d x + c\right )^{8} - 160 \, a^{7} b \cos \left (d x + c\right )^{7} + 1715 \, a^{6} b^{2} - 4725 \, a^{4} b^{4} + 3780 \, a^{2} b^{6} - 840 \, b^{8} - 56 \, {\left (9 \, a^{8} - 4 \, a^{6} b^{2}\right )} \cos \left (d x + c\right )^{6} + 84 \, {\left (9 \, a^{7} b - 4 \, a^{5} b^{3}\right )} \cos \left (d x + c\right )^{5} + 140 \, {\left (6 \, a^{8} - 9 \, a^{6} b^{2} + 4 \, a^{4} b^{4}\right )} \cos \left (d x + c\right )^{4} - 280 \, {\left (6 \, a^{7} b - 9 \, a^{5} b^{3} + 4 \, a^{3} b^{5}\right )} \cos \left (d x + c\right )^{3} - 840 \, {\left (a^{8} - 6 \, a^{6} b^{2} + 9 \, a^{4} b^{4} - 4 \, a^{2} b^{6}\right )} \cos \left (d x + c\right )^{2} + 35 \, {\left (a^{7} b + 153 \, a^{5} b^{3} - 324 \, a^{3} b^{5} + 168 \, a b^{7}\right )} \cos \left (d x + c\right ) + 1680 \, {\left (a^{6} b^{2} - 6 \, a^{4} b^{4} + 9 \, a^{2} b^{6} - 4 \, b^{8} + {\left (a^{7} b - 6 \, a^{5} b^{3} + 9 \, a^{3} b^{5} - 4 \, a b^{7}\right )} \cos \left (d x + c\right )\right )} \log \left (a \cos \left (d x + c\right ) + b\right )}{840 \, {\left (a^{10} d \cos \left (d x + c\right ) + a^{9} b d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.77, size = 1861, normalized size = 6.97 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.59, size = 456, normalized size = 1.71 \[ \frac {\cos ^{7}\left (d x +c \right )}{7 a^{2} d}-\frac {b \left (\cos ^{6}\left (d x +c \right )\right )}{3 a^{3} d}-\frac {3 \left (\cos ^{5}\left (d x +c \right )\right )}{5 a^{2} d}+\frac {3 \left (\cos ^{5}\left (d x +c \right )\right ) b^{2}}{5 d \,a^{4}}+\frac {3 b \left (\cos ^{4}\left (d x +c \right )\right )}{2 a^{3} d}-\frac {\left (\cos ^{4}\left (d x +c \right )\right ) b^{3}}{d \,a^{5}}+\frac {\cos ^{3}\left (d x +c \right )}{a^{2} d}-\frac {3 \left (\cos ^{3}\left (d x +c \right )\right ) b^{2}}{d \,a^{4}}+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right ) b^{4}}{3 d \,a^{6}}-\frac {3 b \left (\cos ^{2}\left (d x +c \right )\right )}{a^{3} d}+\frac {6 \left (\cos ^{2}\left (d x +c \right )\right ) b^{3}}{d \,a^{5}}-\frac {3 \left (\cos ^{2}\left (d x +c \right )\right ) b^{5}}{d \,a^{7}}-\frac {\cos \left (d x +c \right )}{a^{2} d}+\frac {9 \cos \left (d x +c \right ) b^{2}}{d \,a^{4}}-\frac {15 \cos \left (d x +c \right ) b^{4}}{d \,a^{6}}+\frac {7 \cos \left (d x +c \right ) b^{6}}{d \,a^{8}}+\frac {2 b \ln \left (b +a \cos \left (d x +c \right )\right )}{a^{3} d}-\frac {12 b^{3} \ln \left (b +a \cos \left (d x +c \right )\right )}{d \,a^{5}}+\frac {18 b^{5} \ln \left (b +a \cos \left (d x +c \right )\right )}{d \,a^{7}}-\frac {8 b^{7} \ln \left (b +a \cos \left (d x +c \right )\right )}{d \,a^{9}}+\frac {b^{2}}{a^{3} d \left (b +a \cos \left (d x +c \right )\right )}-\frac {3 b^{4}}{d \,a^{5} \left (b +a \cos \left (d x +c \right )\right )}+\frac {3 b^{6}}{d \,a^{7} \left (b +a \cos \left (d x +c \right )\right )}-\frac {b^{8}}{d \,a^{9} \left (b +a \cos \left (d x +c \right )\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.79, size = 271, normalized size = 1.01 \[ \frac {\frac {210 \, {\left (a^{6} b^{2} - 3 \, a^{4} b^{4} + 3 \, a^{2} b^{6} - b^{8}\right )}}{a^{10} \cos \left (d x + c\right ) + a^{9} b} + \frac {30 \, a^{6} \cos \left (d x + c\right )^{7} - 70 \, a^{5} b \cos \left (d x + c\right )^{6} - 126 \, {\left (a^{6} - a^{4} b^{2}\right )} \cos \left (d x + c\right )^{5} + 105 \, {\left (3 \, a^{5} b - 2 \, a^{3} b^{3}\right )} \cos \left (d x + c\right )^{4} + 70 \, {\left (3 \, a^{6} - 9 \, a^{4} b^{2} + 5 \, a^{2} b^{4}\right )} \cos \left (d x + c\right )^{3} - 630 \, {\left (a^{5} b - 2 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{2} - 210 \, {\left (a^{6} - 9 \, a^{4} b^{2} + 15 \, a^{2} b^{4} - 7 \, b^{6}\right )} \cos \left (d x + c\right )}{a^{8}} + \frac {420 \, {\left (a^{6} b - 6 \, a^{4} b^{3} + 9 \, a^{2} b^{5} - 4 \, b^{7}\right )} \log \left (a \cos \left (d x + c\right ) + b\right )}{a^{9}}}{210 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.19, size = 588, normalized size = 2.20 \[ \frac {{\cos \left (c+d\,x\right )}^4\,\left (\frac {b^3}{2\,a^5}+\frac {b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{2\,a}\right )}{d}-\frac {{\cos \left (c+d\,x\right )}^2\,\left (\frac {b^2\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{2\,a^2}+\frac {b\,\left (\frac {3}{a^2}+\frac {b^2\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a^2}-\frac {2\,b\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{a}\right )}{a}\right )}{d}-\frac {{\cos \left (c+d\,x\right )}^5\,\left (\frac {3}{5\,a^2}-\frac {3\,b^2}{5\,a^4}\right )}{d}+\frac {{\cos \left (c+d\,x\right )}^7}{7\,a^2\,d}-\frac {\cos \left (c+d\,x\right )\,\left (\frac {1}{a^2}+\frac {b^2\,\left (\frac {3}{a^2}+\frac {b^2\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a^2}-\frac {2\,b\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{a}\right )}{a^2}-\frac {2\,b\,\left (\frac {b^2\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{a^2}+\frac {2\,b\,\left (\frac {3}{a^2}+\frac {b^2\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a^2}-\frac {2\,b\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{a}\right )}{a}\right )}{a}\right )}{d}+\frac {{\cos \left (c+d\,x\right )}^3\,\left (\frac {1}{a^2}+\frac {b^2\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{3\,a^2}-\frac {2\,b\,\left (\frac {2\,b^3}{a^5}+\frac {2\,b\,\left (\frac {3}{a^2}-\frac {3\,b^2}{a^4}\right )}{a}\right )}{3\,a}\right )}{d}-\frac {b\,{\cos \left (c+d\,x\right )}^6}{3\,a^3\,d}-\frac {-a^6\,b^2+3\,a^4\,b^4-3\,a^2\,b^6+b^8}{a\,d\,\left (\cos \left (c+d\,x\right )\,a^9+b\,a^8\right )}+\frac {\ln \left (b+a\,\cos \left (c+d\,x\right )\right )\,\left (2\,a^6\,b-12\,a^4\,b^3+18\,a^2\,b^5-8\,b^7\right )}{a^9\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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